String Formatting Python Hackerrank solution

Given an integer,n, print the following values for each integer i from 1 to n:

Decimal

Octal

Hexadecimal (capitalized)

Binary

Function Description

Complete the print_formatted function in the editor below.

print_formatted has the following parameters:

int number: the maximum value to print

Prints

The four values must be printed on a single line in the order specified above for i each  from 1 to number. Each value should be space-padded to match the width of the binary value of number and the values should be separated by a single space.

Input Format

A single integer denoting .

Constraints

1≤n≤99

Sample Input

17

Sample Output

    1     1     1     1
    2     2     2    10
    3     3     3    11
    4     4     4   100
    5     5     5   101
    6     6     6   110
    7     7     7   111
    8    10     8  1000
    9    11     9  1001
   10    12     A  1010
   11    13     B  1011
   12    14     C  1100
   13    15     D  1101
   14    16     E  1110
   15    17     F  1111
   16    20    10 10000
   17    21    11 10001

Solution

def print_formatted(number):
    if 1<=number<=99:
        blen = len(str(format(number,"b")))
        for i in range(1,n+1):
            print("{0:d}".format(i).rjust(blen),end=' ')
            print("{0:o}".format(i).rjust(blen),end=' ')
            print("{0:X}".format(i).rjust(blen),end=' ')
            print("{0:b}".format(i).rjust(blen))


if __name__ == '__main__':
    n = int(input())
    print_formatted(n)