This challenge works with a custom-designed markup language HRML. In HRML, each element consists of a starting and ending tag, and there are attributes associated with each tag. Only starting tags can have attributes. We can call an attribute by referencing the tag, followed by a tilde, '~' and the name of the attribute. The tags may also be nested.
The opening tags follow the format:
<tag-name attribute1-name = "value1" attribute2-name = "value2" ...>
The closing tags follow the format:
</tag-name>
The attributes are referenced as:
tag1~value
tag1.tag2~name
Given the source code in HRML format consisting of N lines, Q answer queries. For each query, print the value of the attribute specified. Print "Not Found!" if the attribute does not exist.
Example
HRML listing
<tag1 value = "value">
<tag2 name = "name">
<tag3 another="another" final="final">
</tag3>
</tag2>
</tag1>
Queries
tag1~value
tag1.tag2.tag3~name
tag1.tag2~value
Here, tag2 is nested within tag1, so attributes of tag2 are accessed as tag1.tag2~<attribute>. Results of the queries are:
Query Value
tag1~value "value"
tag1.tag2.tag3~name "Not Found!"
tag1.tag2.tag3~final "final"
The first line consists of two space separated integers,N and Q.N specifies the number of lines in the HRML source program.Q specifies the number of queries.
The following N lines consist of either an opening tag with zero or more attributes or a closing tag. There is a space after the tag-name, attribute-name, '=' and value.There is no space after the last value. If there are no attributes there is no space after tag name.
Q queries follow. Each query consists of string that references an attribute in the source program.More formally, each query is of the form
- Each line in the source program contains, at most,200 characters.
- Every reference to the attributes in the Q queries contains at most 200 characters.
- All tag names are unique and the HRML source program is logically correct, i.e. valid nesting.
- A tag can may have no attributes.
Output Format
Print the value of the attribute for each query. Print "Not Found!" without quotes if the attribute does not exist.
Sample Input
4 3
<tag1 value = "HelloWorld">
<tag2 name = "Name1">
</tag2>
</tag1>
tag1.tag2~name
tag1~name
tag1~value
Sample Output
Name1
Not Found!
HelloWorld
Solution
#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
#include <bits/stdc++.h>
using namespace std;
int main() {
/* Enter your code here. Read input from STDIN. Print output to STDOUT */
int n, q,i;
cin>>n>>q;
string temp;
vector<string> hrml;
vector<string> quer;
cin.ignore();
for(i=0;i<n;i++)
{
getline(cin,temp);
hrml.push_back(temp);
}
for(i=0;i<q;i++)
{
getline(cin,temp);
quer.push_back(temp);
}
map<string, string> m;
vector<string> tag;
for(i=0;i<n;i++)
{
temp=hrml[i];
temp.erase(remove(temp.begin(), temp.end(), '\"' ),temp.end());
temp.erase(remove(temp.begin(), temp.end(), '>' ),temp.end());
if(temp.substr(0,2)=="</")
{
tag.pop_back();
}
else
{
stringstream ss;
ss.str("");
ss<<temp;
string t1,p1,v1;
char ch;
ss>>ch>>t1>>p1>>ch>>v1;
string temp1="";
if(tag.size()>0)
{
temp1=*tag.rbegin();
temp1=temp1+"."+t1;
}
else
{
temp1=t1;
}
tag.push_back(temp1);
m[*tag.rbegin()+"~"+p1]=v1;
while(ss)
{
ss>>p1>>ch>>v1;
m[*tag.rbegin()+"~"+p1]=v1;
}
}
}
for(i=0;i<q;i++)
{
if (m.find(quer[i]) == m.end())
{
cout << "Not Found!\n";
}
else
{
cout<<m[quer[i]]<<endl;
}
}
return 0;
}