Java If-Else HackerRank Solution

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task

Given an integer, n, perform the following conditional actions:

• If n is odd, print Weird
• If n is even and in the inclusive range of 2 to 5, print Not Weird
• If n is even and in the inclusive range of 6 to 20, print Weird
• If n is even and greater than 20, print Not Weird
• Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

• Constraints

1≤n≤200

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0:n=3 

n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n=24

n>20 and n is even, so it isn't weird. Thus, we print Not Weird.

Solution

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        if(n%2==0 && n<=5)
        {
            System.out.println("Not Weird");
        }
        else if(n%2==0 &&n<=20)
        {
            System.out.println("Weird");
        }
        else if(n%2==0 && 20<n)
        {
            System.out.println("Not Weird");
        }
        else
        {
            System.out.println("Weird");
        }
    }
}