Python If-Else Hackerrank solution

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Task

Given an integer,n , perform the following conditional actions:

  • If n is odd, print Weird
  • If n is even and in the inclusive range of  2 to 5, print Not Weird
  • If n is even and in the inclusive range of 6 to 20, print Weird
  • If n is even and greater than 20, print Not Weird

Input Format

A single line containing a positive integer,n.

Constraints

  • 1 ≤  n ≤ 100

Output Format

Print Weird if the number is weird. Otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Explanation 0

n = 3

n is odd an odd numbers are weired, so print weired 


Sample Input 1

24

Sample Output 1

Not Weird

Explanation 1

n = 24

n > 20 and n is even, so it is not weired

import sys



N = int(raw_input().strip())

if N % 2 != 0:
    print "Weird"
else:
    if N >= 2 and N <= 5:
        print "Not Weird"
    elif N >= 6 and N <= 20:
        print "Weird"
    elif N > 20:
        print "Not Weird"

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