Print a pattern of numbers from to as shown below. Each of the numbers is separated by a single space.
4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4
Input Format
The input will contain a single integer .
Constraints
Sample Input 0
2
Sample Output 0
2 2 2
2 1 2
2 2 2
Sample Input 1
5
Sample Output 1
5 5 5 5 5 5 5 5 5
5 4 4 4 4 4 4 4 5
5 4 3 3 3 3 3 4 5
5 4 3 2 2 2 3 4 5
5 4 3 2 1 2 3 4 5
5 4 3 2 2 2 3 4 5
5 4 3 3 3 3 3 4 5
5 4 4 4 4 4 4 4 5
5 5 5 5 5 5 5 5 5
Sample Input 2
7
Sample Output 2
7 7 7 7 7 7 7 7 7 7 7 7 7
7 6 6 6 6 6 6 6 6 6 6 6 7
7 6 5 5 5 5 5 5 5 5 5 6 7
7 6 5 4 4 4 4 4 4 4 5 6 7
7 6 5 4 3 3 3 3 3 4 5 6 7
7 6 5 4 3 2 2 2 3 4 5 6 7
7 6 5 4 3 2 1 2 3 4 5 6 7
7 6 5 4 3 2 2 2 3 4 5 6 7
7 6 5 4 3 3 3 3 3 4 5 6 7
7 6 5 4 4 4 4 4 4 4 5 6 7
7 6 5 5 5 5 5 5 5 5 5 6 7
7 6 6 6 6 6 6 6 6 6 6 6 7
7 7 7 7 7 7 7 7 7 7 7 7 7 #include <stdio.h>
int main()
{
int i,j,k,m,n,x;
scanf("%d",&n);
k=n;
m = n+(n-1);
for(i=0;i<m;i++)
{
for(j=0;j<m;j++)
{
if(i<=n-1)
{
if(i==0)
{
printf("%d ",k);
}
if(i>=1)
{
if(j<i)
{
printf("%d ",k-j);
}
else if(j>=i && j<m-i)
{
printf("%d ",k-i);
}
else
{
printf("%d ",(j-k+1)+1);
}
}
}
else if(i==n-1)
{
if(j<n)
{
printf("%d ",k-j);
}
else
{
printf("%d ",(j-k+1)+1);
}
}
else if(i>=n)
{
x = m-i-1;
if(i==m)
{
printf("%d ",k);
}
if(j<x)
{
printf("%d ",k-j);
}
else if(j>=x && j<m-x)
{
printf("%d ",k-x);
}
else
{
printf("%d ",(j-k+1)+1);
}
}
}
printf("\n");
}
}